json необходимо вывести определенные данные

Question

Есть json, как из него получить определенные данные,например мне необходимо вывести только (id,adress,city,workingHours,coordinates)

"type": "FeatureCollection",
"features": [
    {
        "type": "Feature",
        "id": 0,
        "geometry": {
            "type": "Point",
            "coordinates": [
                "54.101023",
                "37.580223"
            ]
        },
        "properties": {
            "id": 0,
            "address": "ул. Грибоедова, д. 54",
            "terminal": true,
            "alcohol": true,
            "iconContent": 12,
            "city": "2-й Западный",
            "workingHours": "09:00-23:00"
        },
        "options": {
            "iconLayout": "default#image",
            "iconImageHref": "/map_img/placemark.png",
            "iconImageSize": [
                "32",
                "50"
            ],
            "iconImageOffset": [
                "-16",
                "-50"
            ],
            "iconShape": {
                "type": "Rectangle",
                "coordinates": [
                    [
                        -16,
                        -50
                    ],
                    [
                        16,
                        0
                    ]
                ]
            }
        }
    }

Answer 1

$content = '{"type":"FeatureCollection","features":[{"type":"Feature","id":0,"geometry":{"type":"Point","coordinates":["54.101023","37.580223"]},"properties":{"id":0,"address":"ул. Грибоедова, д. 54","terminal":true,"alcohol":true,"iconContent":12,"city":"2-й Западный","workingHours":"09:00-23:00"},"options":{"iconLayout":"default#image","iconImageHref":"/map_img/placemark.png","iconImageSize":["32","50"],"iconImageOffset":["-16","-50"],"iconShape":{"type":"Rectangle","coordinates":[[-16,-50],[16,0]]}}}]}';
$data = json_decode($content);
$out = [
    'id' => $data->features[0]->id,
    'address' => $data->features[0]->properties->address,
    'city' => $data->features[0]->properties->city,
    'workingHours' => $data->features[0]->properties->workingHours,
    'coordinates' => $data->features[0]->geometry->coordinates,
];
echo '<pre>';
var_export($out);
echo '</pre>';

На выходе все что вам нужно:

array (
  'id' => 0,
  'adress' => 'ул. Грибоедова, д. 54',
  'city' => '2-й Западный',
  'workingHours' => '09:00-23:00',
  'coordinates' => 
  array (
    0 => '54.101023',
    1 => '37.580223',
  ),
)

БЛОГ НА HUSL

json необходимо вывести определенные данные

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