вывод округленных значений в словаре и списке

Как получить при выводе округленные значения в словаре 'sum_every_medium' и в списке 'every_order_pure' в python?

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Основной код:

from DefPure import pure

sum_every_medium = {}
every_order_pure = []

with open("data_no_header.txt", 'r') as f:
 for line in f:
    line = line.strip().split('\t')
    medium, roi = pure(line)
    every = '{} : {:.2f}$'.format(medium, roi)
    every_order_pure.append(every)
    if medium in sum_every_medium:
        sum_every_medium[medium] += roi
    else:
        sum_every_medium[medium] = roi

print(sum_every_medium)
print()
print(every_order_pure)

Сама функция:

def pure(line):
    cpa = {
      'burgerclub' : 0.3,
      'food-delefery' : 0.25
    }

    cpc = {
      'city-magazine' : 7,
      'foody' : 9
    }

    fixed = 4

    pure = 0
    orderId = line[0]
    medium = line[-5]
    source = line[-4]
    amount = float(line[-1].replace(',', '.'))
    cost = float(line[-3].replace(',', '.'))

    # cpa pure
    if medium == 'cpa_partner':
        if source == 'burgerclub':
            pure = amount * cpa['burgerclub'] - cost
        else:
            pure = amount * cpa['food-delefery'] - cost

    # cpc pure
    elif medium == 'cpc_partner':
        if source == 'city-magazine':
            pure = amount - (cpa['city-magazine'] + cost)
        else:
            pure = amount - (cpa['foody'] + cost)

    # fixed pure
    else:
        pure = amount - (cost + 4)

    return medium, pure